Answer:
A) 1 inch
Step-by-step explanation:
Answer:
we conclude that the intervals in which the function P(t) is decreasing are:
Step-by-step explanation:
At x< 1, the function P(t) is decreasing
- A function p is an increasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>x
- A function p is a decreasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>x
From the figure, it is clear that the function seems to be increasing
from (1, 3) and then 4 to onwards.
But it is clear that the function seems to be decreasing from the x < 1 and from the interval (3, 4).
Therefore, we conclude that the intervals in which the function P(t) is decreasing are:
Answer: C
Step-by-step explanation:
Step-by-step explanation:
x³ - 4x² - 25x + 100k
= x²(x - 4) - 25(x - 4k)
= (x² - 25)(x - 4k)
= (x + 5)(x - 5)(x - 4k)
Hence the other 2 zeroes are x = -5 or x = 5.
