All categories

4 years ago

What is the suface area of a volleyball with a circumference of 25 inches

Mathematics

1 answer:

torisob [31]4 years ago

8 0

200.96
hope this helped!

You might be interested in

Pls help o have to return this today

maxonik [38]

Answer:

Which part of the story's plot structure does this sentence illustrate? I think its B. Climax

7 0

3 years ago

Simplify (x^-5) (x^2)*

Pani-rosa [81]

Answer:

1/x^3

Step-by-step explanation:

foil method

6 0

3 years ago

What is the inverse function of g(x)=1/x-2

kkurt [141]

Assuming it's $g(x)=\dfrac{1}{x-2}$

$y=\dfrac{1}{x-2}\\ x-2=\dfrac{1}{y}\\ x=\dfrac{1}{y}+2\\ g^{-1}(x)=\dfrac{1}{x}+2$

3 0

3 years ago

ILL MARK BRAINLIST , pls help

Scilla [17]

Answer:

x^2+12x+36=1+36

Step-by-step explanation:

you divide the 12 by 2 which is 6 and then square it (36)

5 0

3 years ago

Read 2 more answers

According to postal regulations, a carton is classified as "oversized" if the sum of its height and girth (the perimeter of its

kotykmax [81]

Answer:

18" X 18" X 36"

Step-by-step explanation:

Given a square base container of height h, let a side of the base =s

The volume of the container, $V= s^2h$

If the sum of its height and girth (the perimeter of its base) equals 108 in

$4s+h = 108\\h = 108-4s$

Substituting h=108-4s into V

$V= s^2(108-4s)$

We are required to determine the maximum volume of such container, first we take the derivative:

$V'(s)= s(216-12s)$

Optimizing:

$s(216-12s)=0\\216-12s=0\\12s=216\\s=216 \div 12\\s=18$

Recall that: h = 108-4s

$h = 108-4(18)=108-72=36inch$

The dimensions of the carton are 18" X 18" X 36".

4 0

3 years ago