Answer:
14.7
Step-by-step explanation:
Perhaps your equation is ...
f(t) = N·e^(-0.2174t)
We want f(6) = 4, so ...
4 = N·e^(-0.2174·6) = N·e^-1.3044 ≈ 0.2713N
N = 4/0.2713 = 14.7 . . . . milligrams
The dose amount was about 14.7 mg.
Looking at the given points on the right side from (0,2) to (1,6) for 1 increase in X ( 1-0=1) the Y value increases by 3 ( 6/2 = 3)
This same increase happens for th other two points: 18/6 = 3
54 / 18 = 3
The rate of increase is 3.