Answer:
2x^2 = 6x - 5.
-x^2 - 10x = 34.
These have only complex roots/
Step-by-step explanation:
3x^2 - 5x = -8
3x^2 - 5x + 8 = 0
There are complex roots if the discriminant 9b^2 - 4ac) is negative.
Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160
This is positive so the roots are real.
2x^2 = 6x - 5
2x^2 - 6x + 5 = 0
D = (-6)^2 - 4*2*5 = 36 - 40 = -4
So this has no real roots only complex ones.
12x = 9x^2 + 4
9x^2 - 12x + 4 = 0
D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.
- Real roots.
-x^2 - 10x = 34
x^2 + 10x + 34 = 0
D = (10)^2 - 4*1*34 = 100 - 136 = -36.
No real roots = only complex roots.
Answer:
14.4
Step-by-step explanation:
Use the Pythagorean Theorem: a^2 + b^2 = c^2
Connie made 60 throws and Sarah made 72.
Hi there!
The correct answer is Rational Number.

:-
Rational Number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator " p " and a non-zero denominator " q ".
~ Hope it helps!
Answer: 49
Step-by-step explanation:
From your question, I think you mean the largest number. The answer is given below.
Let the five consecutive odd numbers be:
a, a+2, a+4, a+6 and a+8.
Thee sum of the first and double the last is 139. This can be written as:
a + 2(a+8) = 139
a + 2a + 16 = 139
3a + 16 = 139
3a = 139 - 16
3a = 123
a = 123/3
a = 41
The first number = 41
The largest number = a+8 = 41 + 8 = 49.