The point-slope form of a line is:
y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line
First we need to find the slope, which is (y2-y1)/(x2-x1)
m=(4--1)/(8-2)
m=5/6 and we can use either point, I'll use (8,4)
y-4=(5/6)(x-8)
That is your equation in point-slope form.
Now the standard equation of a line is ax+by=c
y-4=(5/6)(x-8) we can perform the indicated multiplication on the right side
y-4=(5x-40)/6 multiply both sides by 6
6y-24=5x-40 add 24 to both sides
6y=5x-16 subtract 5x from both sides
-5x+6y=-16 and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1
5x-6y=16
Answer:
x = ± 2, x = 3
Step-by-step explanation:
note that x = 2 gives
2³ - 3(2)² - 4(2) + 12 = 8 - 12 - 8 + 12 = 0
Hence x = 2 is a root and (x - 2) is a factor
x³ - 3x² - 4x + 12 ÷ (x - 2)
= (x - 2)(x² - x - 6)
= (x - 2)(x + 2)(x - 3), hence
(x - 2)(x + 2)(x - 3) = 0
equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
x - 3 = 0 ⇒ x = 3
Answer:
The area of the sector is 17/2 π
Step-by-step explanation:
pi = π
To solve this problem we first have to find the fraction that corresponds to this angle of the total, for this we must divide the angle that they give us by 2π radians, since that is the angle of a circle
(17π/9 rad) / (2π rad) = 17/18
Now we multiply the area of the circle by this fraction and we will obtain the area of the sector that we want
9π * 17/18 = 17/2 π
The area of the sector is 17/2 π
Hello!
The answer is ≈6.63 it's hard to determine an exact decimal, because it is irrational.
Hope this helps! ☺♥
