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rewona [7]
3 years ago
10

The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula

so that it is rewritten to solve for r. Below are various solutions that your group-mates have arrived at. Select the correct one. A r=3V4π−−−√ B r=3V4π−−−√3 C r=3V√34π D r=4V3π−−−√3
Mathematics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

V=\frac{4}{3} \pi r^{3}

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

V=\frac{4}{3} \pi r^{3}   ......Given

3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

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So:

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2log_ {5} (\frac {x} {4})

By definition of logarithm properties we have to:

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Then, rewriting the expression:

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