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Sloan [31]
3 years ago
7

What is the range of function from y = 2x - 2 with the domain 1,2,3 ?

Mathematics
1 answer:
algol [13]3 years ago
6 0
If the domain of <span>y = 2x - 2 is {1, 2, 3}, then the range has only three values:

2(1)-2=0
2(2)-2=2
2(3)-2=4

The range is {0,2,4}.</span>
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What is the domain of f(x)?<br> {x|1 {x|1 {yl-4 {y|-4
Paul [167]

Answer:

1\leq x

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The domain of a function is the set of all possible values of x

The domain of the line with negative slope is the interval [1,3)

The domain of the line with slope equal to zero (horizontal line ) is the interval [3,5)

so

The domain of the piece-wise function is the interval [1,5)

1\leq x

The value of x=1 is included in the domain set

The value of x=5 is not included in the domain set

3 0
4 years ago
What are expressions for MN and LN? Hint Construct the altitude from M to LN.
Nikitich [7]

The question is missing the figure. So, it is in the atachment.

Answer: MN = x\sqrt{2}  LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

Step-by-step explanation: The first figure in the attachment is the figure of the question. The second figure is a way to respond this question by tracing the altitude from M to LN as suggested. When an altitude is drawn, it forms a 90° angle with the base, as shown in the drawing. To determine the other angle, you have to remember that all internal angles of a triangle sums up to 180°.

For the triangle <u>on the left</u> of the altitude:

45+90+angle=180

angle = 45

For the triangle <u>on the right</u>:

30+90+angle=180

angle = 60

With the angles, use the Law of Sines, which is relates sides and angles, as follows:

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

For MN:

\frac{x}{sin(30)} = \frac{MN}{sin(45)}

MN = \frac{x.sen(45)}{sen(30)}

MN = x\sqrt{2}

For LN:

\frac{LN}{sen(105)} =\frac{x}{sin(30)}

LN = \frac{x.sin(105)}{sin(30)}

We can determine sin (105) as:

sin(105) = sin(45+60)

sin(105) = sin(45)cos(60) + cos(45)sin(60)

sin(105) = \frac{\sqrt{2} }{2}.\frac{1}{2} + \frac{\sqrt{2} }{2}.\frac{\sqrt{3} }{2}

sin(105) = \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}

LN = \frac{x.sin(105)}{sin(30)}

LN = x.(\frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}  ) .2

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

The expressions for:

MN = x\sqrt{2}

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

6 0
3 years ago
Please help me I really need it in the next 2 mins first and correct answer gets brainly.est
WITCHER [35]
13 units because 7 + 6 = 13

3 0
3 years ago
Read 2 more answers
An article in the San Jose Mercury News stated that students in the California state university system take 4.5 years, on averag
shtirl [24]

Answer: No, the data does not support the claim at 1% level as the mean time is no longer than 4.5 years.

Step-by-step explanation:

Since we have given that

n the California state university system take 4.5 years, on average, to finish their undergraduate degrees.

So, the hypothesis would be

H_0:\mu=4.5\\\\H_a:\mu>4.5

Mean = 5.1

Standard deviation = 1.2

n = 49

So, test statistic value would be

z=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\z=\dfrac{4.5-5.1}{\dfrac{1.2}{\sqrt{49}}}\\\\z=\dfrac{-0.6}{0.17}\\\\z=-3.53

At 1% level of significance, critical value is 2.58

Since 2.58>-3.53.

So, we will accept the null hypothesis.

Hence, No, the data does not support the claim at 1% level as the mean time is no longer than 4.5 years.

8 0
3 years ago
How do you evaluate 11 c 5
swat32
You have 11 items and you need to choose 5 of the 11.
There are 462 ways to choose them.
The formula is :
11! / (5!6!)
n!/(r!(n-r)!)
6 0
4 years ago
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