Both the macrophages and the neutrophils can discharge their lysosomal enzymes, via exocytosis, into the extracellular fluid or release their entire cell content when the cell ( macrophage or neutrophil) dies. Releasing of these enzymes assists in the digesting of the inflammatory exudate.
Neutrophils wander in the connective tissue killing bacteria, they produce a cloud of bactericidal chemicals which creates a killing zone. Lysosomes discharge contents into tissue fluids through a process called degranulation, the comes the respiratory burst which is when the neutrophils absorb all the oxygen which causes toxic chemicals to be created.
Answer:
She was able to represent something small in a larger way.
Explanation:
Obviously if the bacteria need to be viewed with a microscope, they are extremely small. Darla likely does not have access to a microscope at her house, so using the macaroni and string, she made her own way of "seeing" the bacteria, but in a larger way. B is false because bacteria are small, not large. C is false macaroni do not need to be viewed with a microscope; in fact, this will probably allow you to not see them very well at all. D is false because macaroni wouldn't really show any patterns.
Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
It would be Primary because the lake is it’s starting point and the pollution grew all the way to the factory.
Answer:
The correct answer is statement d.
Explanation:
In oxidative phosphorylation that takes place in mitochondria, the uncouplers prevent the coupling in between the phosphorylation reactions and electron transport, and therefore, prevent the synthesis of ATP without influencing the ATP synthase and respiratory chain.
The uncoupler always exhibits its influence on the synthesis of ATP. The 2,4-dinitrophenol functions as an uncoupler at the time of oxidative phosphorylation. The NADPH and FAD functions as an electron carrier.
