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OlgaM077 [116]
3 years ago
8

A __________ is the column of data in a database that is used as the basis for arranging data.

Computers and Technology
2 answers:
Llana [10]3 years ago
8 0
The answer is sort key.  A Sort Key is the column of data in a database that is used as the basis for arranging data. Iy is also used for rearranging data in the column.  An Operational Database is used to collect, modify, and maintain data on a daily basis.
AnnyKZ [126]3 years ago
7 0

Answer:

Sort key is the correct answer for the above question.

Explanation:

To arrange the data in a database, a user needs to make some filter for the database. This filter is used to sort the data on behalf of some attributes. The sort is a technique in which the data is arranged in synchronously which can be ascending or descending order. The ascending order presents the data in which approach from small index data to large index data and the descending order approach the data from large index to the small index.

The above question asked about the column key through which data of a database can be arranged. So the answer is the sort key because, Sort is a key of operational data that is used to arrange the operation database in the ascending or descending order.

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Suppose we have two String objects and treat the characters in each string from beginning to end in the following way: With one
Simora [160]

Answer:

If all the character pairs match after processing both strings, one string in stack and the other in queue, then this means one string is the reverse of the other.                            

Explanation:

Lets take an example of two strings abc and cba which are reverse of each  other.

string1 = abc

string2 = cba

Now push the characters of string1 in stack. Stack is a LIFO (last in first out) data structure which means the character pushed in the last in stack is popped first.

Push abc each character on a stack in the following order.

c

b

a

Now add each character of string2 in queue. Queue is a FIFO (first in first out) data structure which means the character inserted first is removed first.

Insert cba each character on a stack in the following order.

a   b   c

First c is added to queue then b and then a.

Now lets pop one character from the stack and remove one character from queue and compare each pair of characters of both the strings to each other.

First from stack c is popped as per LIFO and c is removed from queue as per FIFO. Then these two characters are compared. They both match

c=c. Next b is popped from stack and b is removed from queue and these characters match too. At the end a is popped from the stack and a is removed from queue and they both are compared. They too match which shows that string1 and string2 which are reverse of each other are matched.

6 0
3 years ago
When using social​ media, make sure to provide access to all the information needed to accurately process messages by following
Nataly_w [17]

Answer:

Option E i.e., transparency is the correct option.

Explanation:

When any person using social media networks the he always ensure that he gives all the information related accurately about himself because in the social media network there is the transparency of everything except his chat with other but any person get details of the other person only if he is using social media network.

4 0
3 years ago
Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr
drek231 [11]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

 

Hence the output is:

The (shortest) distance between the cars is: 222.56        

3 0
3 years ago
A web directory is a web page that conducts searches of the web to find the words or expressions that you enter? true or false.
Sav [38]
The answer to this is true! hope i helped!
4 0
3 years ago
En un taller tienen dos taladros de sobremesa de 600 w de potencia, una sierra de calar de 500 w y cuatro soldadores de 50 w. Lo
sveticcg [70]

Answer:

El consumo del taller es de 3.7 kw/h.

Explanation:

Dado que el taller posee dos taladros de sobremesa de 600 vatios de potencia, que son utilizados durante 2 horas diarias; una sierra de calar de 500 vatios de potencia que es utilizada durante 1 hora diaria, y cuatro soldadores de 50 vatios que se utilizan durante 4 horas diarias, para medir el consumo diario de energía del taller es necesario realizar el siguiente calculo:

600 x 2 x 2 = 2,400 vatios de consumo taladros

500 x 1 x 1 = 500 vatios de consumo sierra de calar

50 x 4 x 4 = 800 vatios de consumo soldadores

2,400 + 500 + 800 = 3,700 vatios de consumo total

Pasado a kilovatios, el consumo del taller es de 3.7 kw/h.

4 0
2 years ago
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