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Juliette [100K]
3 years ago
15

Consider the following algorithm.. for. i is in {1, 2, 3, 4} do. beep. for j is in {1, 2, 3} do. beep. for k is in {1, 2, 3, 4}

do. for l is in {1, 2, 3, 4, 5} do. beep. for m is in {1, 2, 3, 4, 5, 6} do. beep. How many times does a beep statement get executed?.
Mathematics
1 answer:
Marina86 [1]3 years ago
5 0
In this problem, we are given with different sets or different algorithms. The common elements that are present through all sets is 1, 2, 3 and a beep. The beep is common to all sets given  from i, j, k, l and m. Hence the beep statement was executed five times.
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Answer:

P(A\ and\ B) = \frac{3}{7}

Step-by-step explanation:

<em>Your question is not well presented; (See Attachment for complete details)</em>

<em></em>

Required

Find P(A n B)

where

A = Event that the place is a city

B = Event that the place is in North

The first step is to get the sample space;

Let S represent the sample space;

S = \{India,\ Tokyo,\ Houston,\ Peru,\ New York,\ Tijuana,\ Canada \}

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The next is to list common elements in A and B

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P(A\ and\ B) = \frac{n(A\ and\ B)}{n(S)}

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