Answer:
x = 5, the data type is integer( integer data type is for whole numbers)
2. The data type is string
3. The data type is float (float data type is for decimals)
Explanation:
The bachelor's program at Eth Zurich is 3 years.
I hope this helps!
:-)
Answer:
Flex direction
Explanation:
HTML is an acronym for hypertext markup language and it is a standard programming language which is used for designing, developing and creating web pages.
Generally, all HTML documents are divided into two (2) main parts; body and head.
The head (header) contains information such as version of HTML, title of a page, metadata, link to custom favicons and cascaded style sheet (CSS) etc.
On the other hand, the body of a HTML document contains the contents or informations that a web page displays.
Generally, the part of a HTML document where the cascaded style sheet (CSS) file is linked is the header.
A style sheet can be linked to an HTML document by three (3) main methods and these are;
I. External style.
II. Inline style.
III. Embedded (internal) style.
Flex direction is a CSS property that's used to determine whether flex items are displayed horizontally or vertically.
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
</span>
As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
I think it's Graph Search because there isn't any graphs in Facebook. That is my opinion. I don't use social media.
