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2 years ago

find 3 consecutive even integers such that the sum of the smaller 2 is 6 less than twice the largest one

Mathematics

1 answer:

saw5 [17]2 years ago

6 0

n, n + 2, n + 4 - three consecutive even integers

n + 2 = 2(n + 4) - 6 |use distributive property

n + 2 = (2)(n) + (2)(4) - 6

n + 2 = 2n + 8 - 6

n + 2 = 2n + 2 |subtract 2 from both sides

n = 2n |subtract 2n from both sides

-n = 0

n = 0

n + 2 = 0 + 2 = 2

n + 4 = 0 + 4 = 4

Answer: 0, 2, 4.

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mr_godi [17]

We determine line m as follows:

*First, by theorem we have the following:

$m_1=-\frac{1}{m_2}$

Here m1 & m2 are the slopes of two perpendicular lines. For all lines that are perpendicular that is true, so we calculate the slope of line m using the slope of the function given [Which has a slope of 7/4]:

$m_1=-\frac{1}{\frac{7}{4}}\Rightarrow m_1=-\frac{4}{7}$

So, the slope of line m is -4/7. Now, using this slope and the point (-1, 4) we replace in the following expression:

$y-y_1=m_1(x-x_1)$

Here x1, y1 & m1 are the x-component of the point, the y-component of the point, and the slope of the line respectively, so we replace and solve for y: