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yan [13]
3 years ago
12

find 3 consecutive even integers such that the sum of the smaller 2 is 6 less than twice the largest one

Mathematics
1 answer:
saw5 [17]3 years ago
6 0

n, n + 2, n + 4 - three consecutive even integers

n + 2 = 2(n + 4) - 6     |use distributive property

n + 2 = (2)(n) + (2)(4) - 6

n + 2 = 2n + 8 - 6

n + 2 = 2n + 2     |subtract 2 from both sides

n = 2n       |subtract 2n from both sides

-n = 0

n = 0

n + 2 = 0 + 2 = 2

n + 4 = 0 + 4 = 4

Answer: 0, 2, 4.

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

a.) Initial cost of renting the car is $100

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5 0
2 years ago
Remi invests £600 for 5 years in a savings account.
Daniel [21]

Answer:

225600

Step-by-step explanation:

Simple interest formula:

A = P(1 + rt)

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P = initial principal balance

r = annual interest rate

t = time (in years)

So...

A = 600(1 +(75 x 5) )

75 x 5 = 375

1 + 375 = 376

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3 years ago
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3 years ago
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Natali5045456 [20]

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3 0
2 years ago
This table shows numbers of sweets in some tubes, but a coffee stain has deleted one of the figures.
svlad2 [7]
To get the answer, you need to think of it like a see-saw.
Both sides must equal the same relative to 33.5. For example, 32 is 1.5 away from 33.5 so you could say you have 1.5*4 (because theres 4 tubes with 32 sweets). If you were to do this for the whole table, it would look something like this:

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This simplifies to:

6+0.5x=8.5
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This method can sometimes be inefficient depending on how many values but is probably the simplest way to solve this problem.

hope this helps :)

(sorry the other way is kinda hard to explain possibly ask your teacher tomorrow)
6 0
3 years ago
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