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nexus9112 [7]
4 years ago
13

Integer questions. Thank you!

Mathematics
1 answer:
andrezito [222]4 years ago
4 0
3. We can see that
1+100=101
2+99=101
3+98=101
.................
and so on
From 1 to 100, there are 50 pairs that has the sum is 101
Z=101×50=5050
4. We can see that
1-2=-1
3-4=-1
5-6=-1
...........
and so on
There are 10 pairs that has sum is -1
Z= 10×(-1)=-10
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Help please thank you!
PSYCHO15rus [73]

Answer: Possibly the first

Step-by-step explanation:

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2 years ago
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Given: KLMN is a trapezoid, KF = 1, MF ║ LK , altitude −h. Area of KLMF = AFMN. Find: KN
Xelga [282]
It's 3 units due to the fact that KF is = to 1 and you need it to have the same area of the triangle. So I got 3

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Which number line best shows the position of 172
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Line 5 looks to be the best one
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Function f(z)=2z-(3+i)
Archy [21]
F(z) = 2z - (3+i)

1) second interate for z0 = i

first iterate = f(z0) = f(i) = 2i - 3 - i = i - 3 = z1
second iterate = f(z1) = f(i-3) = 2(i-3) - 3 - i = 2i - 6 - 3 - i = i - 9

2) third iterate for z0= 3 - i

first iterate = f(z0) = f(3 - i) = 2(3-i) - (3+i) = 6 -2i -3 - i =3 - 3i = z1
second iterate = f(z1) = f(3 -3i) = 2(3-3i) - (3+i) = 6 - 6i -3 -i = 3 - 7i = z2
third iterate = f(z2) = f(3 - 7i) = 2 (3-7i) - (3+i) = 6 - 14i - 3 - i = 3 -15i = z3.

3) first iterate for z0=0.5+i

first iterate = f(z0) = f(0.5 +i) = 2(0.5+i) - (3+i) = 1 +2i - 3 - i = - 2 + i = z1

4) third iterate for z0=-2-5i

first iterate = f(z0) = 2(- 2 - 5i) - (3 + i) = - 4 - 10i - 3 - i = -7 - 11i = z1
second iterate = f(z1) = 2( - 7 - 11i) - (3+i) = -14 - 22i - 3 - i = -17 -23i = z2
third iterate = f(z2) = 2(-17-23i) -(3+i) = -34 - 46i -3 - i = -37 - 47i = z3
8 0
3 years ago
Type an equation to show two times a certain number is 8. (Use x as the unknown variable.)
Temka [501]
The answer ; 2(x)=8 let x represent the unknown number, and by putting 2 infront shows it is being multipled by X .
7 0
3 years ago
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