8
8
17
20
321
400
Go from left to right on each row :)
The object's maximum height is the same as the y-coordinate of the vertex.To find that, first, finds the x- coordinate(t).You can find it by:
first identifying a,b and c.Multiply the b by negative 1 or simply change its sign and divide it by 2a.Afterward, plug the answer in the equation to find y, your answer.
(ax+bx²+c=-16t²+64t+80). Therefore, a=-6, b= 64 and c=80
-64/2(-16)=-64/-32=2
-16(2)²+64(2)+80=144 ft
So the maximum height of the object, when launched 64ft/sec from a platform that is 80 ft high, is 144 ft
Hope this helps(there are other methods)
Answer:
A. Use the Subtraction Property of Equality to subtract 4x from both sides of the equation.
Step-by-step explanation:
Given equation is 4x + 5y = 10
we have to convert it in slope intercept form
slope intercept form is given by y = mx + c
now seeing the slop intercept form ,
we can say that
we have to isolate y , for that we have to remove 4x from
4x + 5y = 10 from RHS of the equation
to do that we have to subtract 4x from both side as shown below
4x + 5y - 4x = 10 - 4x
this step is called Subtraction Property of Equality to subtract 4x from both sides of the equation
and hence option A is the correct choice
Answer:
40.32 cm²
Step-by-step explanation:
The area of the small rectangle = 7 × 4 = 28 cm²
Given the ratio of the sides of similar rectangles = a : b , then
the ratio of the areas = a² : b²
Here ratio of sides = 4 : 4.8 = 1 : 1.2
ratio of areas = 1² : 1.2² = 1 : 1.44
Let x be the area of the larger rectangle then by proportion
=
( cross- multiply )
x = 40.32
Area of larger rectangle is 40.32 cm²