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suter [353]
3 years ago
9

Is the following function even, odd, or neither? f(x)=2|x|-5

Mathematics
1 answer:
pshichka [43]3 years ago
5 0

Answer:

parity of 2x-5 is neither even nor odd

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2L plus 2L plus 1.5L plus 2.5L=8L just making shore it is right?
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Step-by-step explanation:

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Which expression gives the determinant of the matrix
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If the matrix is of 2 by 2 then we can find the determinant of the matrix.

\begin{bmatrix}a & b\\ c & d\end{bmatrix}

Then (ad - bc ) gives you the determinant of the matrix.

For example,

\begin{bmatrix} 2 & 4\\  1 & -2 \end{bmatrix}

= (2)(-2) - (1)(4)

= - 4 - 4

\begin{bmatrix} 2 & 4\\  1 & -2 \end{bmatrix} = -8



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Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se
kolbaska11 [484]

Answer:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

Step-by-step explanation:

Given:

The expression to expand is given as:

(x-3)(x-9)(x-4)

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

(a + b)(c + d) = ac + ad + bc + bd

(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)

Therefore, the equivalent expression after expanding is given as:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

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Answer:

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