Ask question

Ask question

All categories

2 years ago

13

What is the measure of ∠F? Irregular quadriateral. Reading clockwise, the angles are labeled one hundred thirty-two degrees, six

ty-eight degrees, F, and sixty-six degrees

1 answer:

Delvig [45]2 years ago

5 0

Total of all angles should equal 360 degrees. So 360-132-68-66=94, angle F is 94 degrees.

You might be interested in

Need help with b and c

xz_007 [3.2K]

Answer:

Step-by-step explanation:

the formula is:

$a_n = \frac{n+1}{n+2}$

[tex]a_100 = \frac{101}{103}[\tex]

5 0

3 years ago

Read 2 more answers

What is the slope in an equation

iris [78.8K]

Answer:

M is the slope

Step-by-step explanation:

In the equation y=mx+b the slope is the number “m” that is multiplied by the x and “b” is the y intercept

6 0

3 years ago

Solve: 28 − ≥ 7( − 4)<br> (show your work)<br> real answers only pls :(

ohaa [14]

You’ll distribute the 7 from (x-4) so your equation will be
28-x>_ 7x-28
then you’ll combine like terms (-x and 7x and 28 and -28
-56>_ -8x
divide by -8 on both sides and flip your sign
you’re answer is x<_7
x is less then or equal to 7

6 0

2 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result:

$\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}$ .

Therefore:

$\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}$ .

Lookup $0.1985$ on a normal distribution table. The corresponding $z$ -score is $0.52$ . (In other words, $P(0 \le Z \le 0.52) = 0.1985$ .)

Given that

$z = 0.52$ ,
$x =5$ , and
$\sigma = 2$ ,

Solve the equation $\displaystyle z = \frac{x - \mu}{\sigma}$ for the mean, $\mu$ :

$\displaystyle 0.52 = \frac{5 - \mu}{2}$ .

$\mu = 5 - 2 \times 0.52 = 3.96$ .

3 0

3 years ago

Evaluation: Flight of the Albatross

aev [14]

Answer:

Step-by-step explanation:

400/8=50

8 0

3 years ago

Read 2 more answers