Hey there!
So, when finding who completed more, we would want to find the lowest denominator, but also, we would have to compare it with the numerator.
John: He completed 2/3, which is basically almost done.
Sarah: She only completed (half) of her homework.
Alex: He only did 7/8
Michelle: He/she only did 1/2, which is only half.
So, from looking at these fractions above, Michelle and Sarah are out.
We would just have to determine, which is finished more, John or Alex.
John had 2/3 & Alex 7/8
So, by comparing them both, 7/8 would be greater because the smaller the denominator is, and the closer that the numerator is to the denominator, this would mean that the homework is almost finished.
Your correct answer is Alex, he has completed more.
Hope this helps you!
Answer: Option 'B' is correct.
Step-by-step explanation:
since we have given that
Time taken to build a cabinet by Genna = 4 hours.
Time taken to build a cabinet by Claude = 3 hours
Now, time taken by both Genna and Claude to build a cabinet together is to be find.
Work done by Genna is given by
Work done by Claude is given by
According to question,
Hence, Option 'B' is correct.
Answer:
1. 24
2. 26
3. 20
4. 20
5. 19
6. 17
Step-by-step explanation:
(sorry if wrong)
Answer:
12 miles
Step-by-step explanation:
Let the amount of hours it takes Leroy to catch up to Kevin equal x. Since speed multiplied by time is distance, Leroy would have run a total of 6x miles(6*x). Kevin already had a head start of 24 minutes, which is the same as 2/5 of an hour. In 2/5 an hour, Kevin ran 2 miles as 2 is 2/5 *5. For the next x hours his distance would be a total of 5x(5*x). This means, after x hours, Kevins distance is 5x + 2. In this case, catching up to someone is the same as having the same distance value. This means we can set the two expressions equal to each other, and solve:
6x = 5x + 2
x = 2
The time it took Leroy to catch up is 2 hours, but we are looking for the distance, which is represented by 6x. We substitute in 2 to get:
6(2) = 12
This means Leroy had to run 12 miles.
Answer:
Step-by-step explanation:
h = -6
+20t + 4
I will use calculus, maybe that's not how you're supposed to do this
-12t +20 =0
12t = 20
t = 20 /12
t = 1 
t = 1 
there will be a max at 1.6666666666 seconds
-6*
+ 20 * 1.6666666666 +4
= 16.666666666666 + 33.333333333333 + 4
= - 16 + 33 + 4
= 20 feet max height ( not too high, for a rocket)
time of flight:
0 = -6 +20t + 4
use quadratic formula to find t
-20 +- sqrt [ 
- 4*(-6)*4 ] / 2*(-6)
-20 +- sqrt [400 + 96 ] / -12
-20 +- sqrt [496 ] / -12
-20 +- 22.27105 / -12
try the negative option 1st
-42.27105 / -12
3.522 seconds. time of flight
when will the rocket be at 12' ? :
12 = -6 +20t + 4
0 = -6 +20t -8
use quadratic formula again to find t
-20 +- sqrt [ - 4*(-6)*(-8) ] / 2*(-6)
-20 +- sqrt [ 400 - 192 ] / -12
-20 +- sqrt [208 ] / -12
-20 - 14.4222 / -12
-34.4222 / -12
2.8685 seconds ( on the way down)
and
-20 + 14.4222 / -12
-5.578 / - 12
0.4648 seconds ( on the way up )
