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mixas84 [53]
3 years ago
8

Party trays, which cost $14.00 to make not including labor, are sold for $35.00. If two people work 8-hour shifts making the tra

ys at $7.00 per hour, how many trays must be sold to cover all costs including labor?
Mathematics
2 answers:
umka21 [38]3 years ago
4 0

Answer:

5.33 trays must be sold to cover all costs including labor...

Step-by-step explanation:

We have given:

Party trays, which cost $14.00 to make not including labor, are sold for $35.00.

Profit on party trays excluding labour cost = $35 - $14 = $21

Now we will find total labor cost for making party tray for a day

Total labor hours * wages per hour* No. of labors

= $7 * $8*2

= $112

Therefore to find how many trays must be sold to cover all costs including labor just divide total labour cost for making party tray for a day by profit on party trays excluding labour cost.

= $112/$21

= 5.33

It means 5.33 trays must be sold to cover all costs including labor...

Arturiano [62]3 years ago
4 0

Answer:

I'm pretty sure it's (5)

Step-by-step explanation:

14 \times 8 = 112

7 \times 8 = 56

112 + 56 = 168

168 \div 35 = 4.8

So approximately 5 trays to cover the cost.

I hope this helps: )

Please let me know if I'm correct.

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