The molar solubility of Ba₃(PO₄)₂ is its concentration of pure substance
The correct equation for the ksp is Ksp = 6x⁵
<h3>How to determine the
equation of ksp?</h3>
Start by writing the reaction for the solution of Barium phosphate
Ba₃(PO₄)₂ ⇌3Ba²⁺ +2PO₄³⁻
Next, we make an ICE chart
Let "x" be the molar solubility of Barium phosphate
Ba₃(PO₄)₂(s) ⇌3Ba²⁺ +2PO₄³⁻
I 0 0
C +3x +2x
E 3x³ 2x²
Lastly, we write the expression for the solubility product constant (Ksp)
This is represented as:
Ksp = [3Ba²⁺] × [2PO₄³⁻]²
Ksp = 3x³ × 2x²
Evaluate the product
Ksp = 6x⁵
Hence, the correct equation for the ksp is Ksp = 6x⁵
Read more about molar solubility at:
brainly.com/question/9732001
Answer:
240 is the mark down.
Step-by-step explanation:
1 - .20 = 0.8
0.8 x 300 = 240
Answer:
Principal Amount x Interest Rate
Step-by-step explanation:
