If f(x) = (2x+9)^3, f '(x) = 3(2x+9)^2*(2), or f '(x) = 6(2x+9)^2. Here we used the power rule with chain rule to find the derivative.
The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
Answer:
number 9 is c.
im not really sure what 10 is
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➷ It would be done in the same way it would if it was an integer ;
think of it as two separate parts
(3/5)^3 = 3/5 * 3/5 * 3/5
Calculate the top half, then the bottom half and put them together
3 * 3 * 3 = 27
5 * 5 * 5 = 125
Thus, your answer will be 27/125
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➶ Hope This Helps You!
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