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evablogger [386]
3 years ago
10

Help!!!!!!!!!!!! Pls

Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0
B is the awser ok got it now
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Over the first five years of owning her car, Gina drove about 12,200 miles the first year, 16,211 miles the second year, 12,050
attashe74 [19]
The answer is <span>mean = 13,027; median = 12,200; no mode
</span>
Let's rearrange values from the lowest to the highest:
11350, 12050, 12200, 13325, 16211

<span>The mean is the sum of all values divided by the number of values:
</span>(11350 + 12050 + 12200 + 13325 + 16211)/5 ≈ 13027

The median is the middle value. If there is an odd number of data, then the median is the value in the middle. In the data set 11350, 12050, 12200, 13325, 16211, the median (the middle value) is 12200

<span>The mode is the value that occurs most frequently. Since none of the number does not occur most frequently, there is no mode.
</span>
7 0
2 years ago
Read 2 more answers
How do these U.S. customary units of liquid volume compare? Drag and drop the volume measures so they are in order from smallest
Bingel [31]

Answer:

it should go cup pint quart.

6 0
3 years ago
Lucinda leaves money in her savings account for 8 years. She started with $800 and earned 3.5% interest compound annually. How m
wariber [46]
I think she would have $1,058.07
8 0
3 years ago
"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

    ve^{kt} = \frac{g}{k}e^{kt} + c

    v(t)=   \frac{g}{k} + ce^{-kt}.

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

       c = 9.55 -16.33 = -6.78.

So, v(t)=   16.33 - 6.78e^{-16.33t}. m/s = - 6.78e^{-16.33t} + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78e^{-16.33 x 0.5} + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

6 0
2 years ago
What what is the mean of the cars
tatuchka [14]
Mean is the average. to find mean, you add all the numbers and divide it by how many numbers there are.

68 + 75 + 85 + 80 + 75 + 82 = 465

There are 6 numbers. That means you have to divide 465 by 6 to get the mean.

Divide:

465 / 6 = 77.5

The answer is D. 77.5

Hope this helped☺☺

8 0
3 years ago
Read 2 more answers
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