The answer is A. 88.8 cm2
Work:
74 x 2 = 148
14.8 = 29.6
Add them = 177.6
then 
I am not completely sure if tis is correct. I just took 16 and multiply them for the answer B and C. hope this can help you.
Answer:
<h3>
There is one unique real number solution at (–1, –3)</h3>
Step-by-step explanation:
Given the two linear equation
–4x – 7 = y ...1
x² – 2x – 6 = y ...2
Equating the left hand side of both equations since they are equal to the same variable y will give;
Substituting x=1 into equation 1 we have;
This means there is only one unique real number solution at (-1, -3)
The room is a square, meaning all four sides are 20ft long.
Because we know all the side lengths, we can find the perimeter of the square by adding the side lengths together.
(20 + 20 + 20 + 20) = 80
Now that we know the perimeter, we have to match this number to the feet of crepe paper.
We can find this by dividing the total length needed by the length a single roll provides.
80 / 8 = 10
Therefore, we know that Katie will have to buy a minimum of 10 rolls if she wants to cover the entire perimeter of the room.
Hope this helps! :)
Answer:
Explanation:
These steps explain how you estimate the age of the parchment:
1) Carbon - 14 half-life: τ = 5730 years
2) Number of half-lives elapsed: n
3) Age of the parchment = τ×n = 5730×n years = 5730n
4) Exponential decay:
The ratio of the final amount of the radioactive isotope C-14 to the initial amount of the same is one half (1/2) raised to the number of half-lives elapsed (n):
5) The parchment fragment had about 74% as much C-14 radioactivity as does plant material on Earth today:
- ⇒ ln (0.74) = n ln (1/2) [apply natural logarithm to both sides]
- ⇒ n = ln (1/2) / ln (0.74)
- ⇒ n ≈ - 0.693 / ( - 0.301) = 2.30
Hence, 2.30 half-lives have elapsed and the age of the parchment is:
- τ×n = 5730n = 5730 (2.30) = 13,179 years
- Round to the nearest hundred years: 13,200 years
