Given the following which is the mean and standard deviation of
the dune’s movement over one year and need to find out what the ten year mean
and the standard deviation will be.
The ten-year mean is ten times the one year mean or 110 feet per
decade. The ten-year standard deviation is somewhat more complicated. Multiple independent
trials accumulate standard deviation as the square root of the number of trials
since an unusually high level of movement ten years in a row. The decade is
going to be 2 feet per year x square root of ten will result to 6.32 feet.
The answer will to question A. will be:
<span> 90 < 110 + z (6.32 feet)</span>
<span> -20 < z (6.32 feet)</span>
<span> z > - 3.16</span>
<span>By using the z table, it shows the probability of 0.9992. This
result shows that as 90 feet is lesser than the mean travel that is expected
over decade. </span>
8(1.65)R + 98.70 = 242.58 13.20R = 143.88 [subtract 98.70 from both sides] R = $10.90 / hr. [divide both sides by 13.20]
5/6y-2=8
+2 +2
Add the reciprocal to cancel out the twos andd 8+2=10
so you have left 5/6y=10 and you'll take the reciprocal of 5 divided by 6 times five and cancels the 5/ out and also multiply 10*5 and you're left with 6y=50 then you just divide by six and there you go you have y=12
hope this helped
Answer:
x = 1
Step-by-step explanation:
3x + 1/2 (2x + 6) = 6x + 1
3x + x + 3 = 6x + 1
4x + 3 = 6x + 1
2 = 2x
x = 1
Answer:
2 = 76p
Step-by-step explanation:
a = pw amount = percent times whole