Answer:
x=1
Step-by-step explanation:
If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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Umm I didn't get a domain.... No solutions were found...
Answer:
Look for perpendicular lines or corresponding angles or alternate interior angles.
Step-by-step explanation:
When you want to show that a quadrilateral is a parallelogram you need to show that the oposite sides are parallel. In order to show that two segments are parallel there are various theorems and definitions you can use.
1 - Remember that two lines perpendicular to the same segment are parallel.
2 - When two lines are cut by a secant and their alternate interior angles are congruent, then the resulting lines are parallel, I will attach a drawing to illustrate what I am saying.
3 - When two lines are cut by a secant and their CORRESPONDING angles are congruent, then the resulting lines are parallel, I will also attach a drawing to illustrate what I am saying.
Answer:
1/3 + 3/4 + 4/6 +1/2 =
Step-by-step explanation:
1/6 + 4/6 = 5/6
3/4 + 1/4 = 4/4
5/6 + 4/4 = 9/12