.89($26,500)=$23,585. we are using .89 because that is what 1-.11 equals.
Answer:
Step-by-step explanation:
Now to find the sum of first 20 terms, substitute n=20,a=−1 and d=4 in S n = 2n [2a+ (n−1)d] as follows: S 20 = 220 [(2×−1)+(20−1)4]=10[−2+(19×4)]=10(−2+76)=10×74=740 Hence, the sum of first 20 terms is 740.
Answer:
60.8$
Step-by-step explanation:
2(6.22)+3(5.33)+5(8.62)=12.44+15.99+43.1=71.53
71.53_0.15(71.53)=60.8$
This involves basic arithmetic calculations and simultaneous equations.
Adamu has 25 Cards
Let the following letters represent the number of cards each has;
A: ADAMU
F: FUNKE
S: SHEHU
K: KWAME
T: TANKO
- If adamu gives funke 5 cards, he will have as many as tanko. Thus;
A - 5 = T --- eq 1
- If funke gives adamu 4 cards, he will have as many as kwame. Thus;
A + 4 = K --- eq 2
- Funke and adamu have a total of 13 more cards than the total that kwame and tanko have. Thus;
A + F = K + T + 13 --- eq 3
- Adamu has 2 cards more than what Shehu has. Thus;
A - 2 = S --- eq 4
From online research, the Total Number of cards is 134 and not 133. Thus;
A + F + K + S + T = 134 --- eq 5
Let's put A - 5 = T and A + 4 = K in eq 3 to get;
A + F = (A + 4) + (A - 5) + 13
A + F = 2A + 12
F = 2A - A + 12
F = A + 12
Let's put A - 2 = S ; F = A + 12 ; A - 5 = T and A + 4 = K into eq 5 to get;
A + A + 12 + A + 4 + A - 2 + A - 5 = 134
Simplifying gives;
5A + 9 = 134
5A = 134 - 9
5A = 125
A = 125/5
A = 25
Adamu has 25 Cards
