Answer:
D. m = 20 , n = 10.
Step-by-step explanation:
The sine of 60 is √3/2, so
sin 60 = 10√3 / m = √3/2
√3 m = 20 √3
Divide both sides by √3:
m = 20.
cos 60 = 1/2 = n / 20
2n = 20
so n = 10.
When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.
For example:
or ![\frac{x^{-3}}{1} =\frac{1}{x^3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B-3%7D%7D%7B1%7D%20%3D%5Cfrac%7B1%7D%7Bx%5E3%7D)
or ![y^2](https://tex.z-dn.net/?f=y%5E2)
![2^{-3}=\frac{1}{2^3} =\frac{1}{8}](https://tex.z-dn.net/?f=2%5E%7B-3%7D%3D%5Cfrac%7B1%7D%7B2%5E3%7D%20%3D%5Cfrac%7B1%7D%7B8%7D)
#1: ![2^5=2*2*2*2*2=32](https://tex.z-dn.net/?f=2%5E5%3D2%2A2%2A2%2A2%2A2%3D32)
#2.
Make the exponent positive ![\frac{1}{2^4} =\frac{1}{2*2*2*2} =\frac{1}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5E4%7D%20%3D%5Cfrac%7B1%7D%7B2%2A2%2A2%2A2%7D%20%3D%5Cfrac%7B1%7D%7B16%7D)
#3:
Make the exponent positive ![\frac{1}{5^2} =\frac{1}{5*5} =\frac{1}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%5E2%7D%20%3D%5Cfrac%7B1%7D%7B5%2A5%7D%20%3D%5Cfrac%7B1%7D%7B25%7D)
#4. ![5^3=5*5*5=125](https://tex.z-dn.net/?f=5%5E3%3D5%2A5%2A5%3D125)
Answer:
x = 19
Step-by-step explanation:
The work shown is almost complete. It can be finished by multiplying both sides of the equation by the inverse of the coefficient of x.
x-coefficient: -1/3
inverse of x-coefficient = 1/(-1/3) = -3
Then you have ...
![-3\left(-\dfrac{19}{3}\right)=-3\left(-\dfrac{1}{3}x\right)\\\\19=x\qquad\text{simplify}\\\\\boxed{x=19}](https://tex.z-dn.net/?f=-3%5Cleft%28-%5Cdfrac%7B19%7D%7B3%7D%5Cright%29%3D-3%5Cleft%28-%5Cdfrac%7B1%7D%7B3%7Dx%5Cright%29%5C%5C%5C%5C19%3Dx%5Cqquad%5Ctext%7Bsimplify%7D%5C%5C%5C%5C%5Cboxed%7Bx%3D19%7D)
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The closest square number is 324 (which is 18^2)
324 - 320 = 4
The number that needs to be added is 4
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Answer:
1
Step-by-step explanation: