Answer:
f(42) = 12
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x/3 - 2
f(42) is x = 42
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: f(42) = 42/3 - 2
- Divide: f(42) = 14 - 2
- Subtract: f(42) = 12
Answer:
Step-by-step explanation:
![\text{We have a rectangle of 100 by 50 and half a circle with a radius of 25.}\\ \\ A=100(50)+3.14(25^2)\\ \\ A\approx 6962.5\ m^2](https://tex.z-dn.net/?f=%5Ctext%7BWe%20have%20a%20rectangle%20of%20100%20by%2050%20and%20half%20a%20circle%20with%20a%20radius%20of%2025.%7D%5C%5C%20%5C%5C%20A%3D100%2850%29%2B3.14%2825%5E2%29%5C%5C%20%5C%5C%20A%5Capprox%206962.5%5C%20m%5E2)
Answer:
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Step-by-step explanation:
Let a, b, and c be the length of 3 corresponding sides of the triangle. The following inequality must always be true since they form a triangle :
![a+b>c](https://tex.z-dn.net/?f=a%2Bb%3Ec)
(This inequality says that the sum of two sides must always be greater than the other side)
Let's use this inequality for x, 1.3, and 4.1
![x+1.3>4.1](https://tex.z-dn.net/?f=x%2B1.3%3E4.1)
(The reason why 1.3 is on the left side is because it is the smaller side)
Subtract both sides by 1.3
![x>2.8](https://tex.z-dn.net/?f=x%3E2.8)
x must always be greater than 2.8. Now, let's see what value x must be always less than.
![1.3+4.1>x](https://tex.z-dn.net/?f=1.3%2B4.1%3Ex)
![5.4>x](https://tex.z-dn.net/?f=5.4%3Ex)
x must be always less than 5.4. Let's combine both statements for x and we get:
![2.8](https://tex.z-dn.net/?f=2.8%3Cx%3C5.4)
These are the only values of x that will make it possible for these sides to form a proper triangle.
Let me know if you need any clarifications, thanks!
~ Padoru
The ratio of the circumferences equals the ratio of the radii.
so we need to find their radii
first circle's radius:
pir^2 = 6pi
r = √6
second circle's radius:
pir^2 = 150pi
r = √150
Their ratio is
√6 : √150 =
√6 : √6√25 =
√6 : 5√6 =
1 : 5