You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Long division is like a bus stop method if you know
so example the set out would be like this
Answer:
x + 2y ≤ 100 and x + 3y ≤ 400
Maximum profit = 6x + 5y.
Step-by-step explanation:
Let there be x number of small dishes and y number of large dishes to maximize the profit.
So, total profit is P = 6x + 5y .......... (1)
Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.
So, as per given conditions,
x + 2y ≤ 100 ........ (1) and
x + 3y ≤ 400 .......... (2)
Therefore, those are the constraints for the problem. (Answer)
Answer:
Step-by-step explanation:
x^2+14x+45=0
x^2+(9+5)x+45=0
x^2+9x+5x+45
x(x+9)+5(x+9)=0
(x+9)(x+5)=0
either x+9=0 Or,x+5=0
x+9=0
x=0-9
x=-9
x+5=0
x=0-5
x=-5
therefore x=-9,-5
Answer:
In exercises 3 and 4,write an equation of the line that passes through the given point and is parallel to the given line. 3. (1,3); y=2x-5 4. (-2,1); y= -4x+3 *In exercises 5 and 6, determine which of the lines,if any, are parallel or perpendicular. Explain! 5. line a passes through (-2,3) and (1,-1). Line b passes through (-3,1) and (1,4). Line c passes through (0,2) and (3,-2). 6. Line a: y= -4x +7 Line b: x= 4y+2 Line c: -4y+x=3 *In exercises 7 and 8, write an equation of the line that passes through the given point and is perpendicular to the given line. 7. (2,-3); y= 1/3x -5 8.(6,1); y= -3/5x-5 * In exercises 11-13, determine whether the statement is sometimes,always, or never true. Explain your reasoning! 11. A line with a positive slope and a line with a negative slope are parallel. 12. A vertical line is perpendicular to the x-axis. 13. two lines with the same x-intercept are perpendicular.
Step-by-step explanation:
