Answer:The quadratic formula helps us solve any quadratic equation. First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula: (-b±√(b²-4ac))/(2a) .The four methods of solving a quadratic equation are factoring, using the square roots, completing the square and the quadratic formula.

Step-by-step explanation: 6x² + 11x - 35 = 0.

2x² - 4x - 2 = 0.

-4x² - 7x +12 = 0.

20x² -15x - 10 = 0.

x² -x - 3 = 0.

5x² - 2x - 9 = 0.

3x² + 4x + 2 = 0.

-x² +6x + 18 = 0.

8 0

3 years ago

A train arrives at a station and waits 2 min before departing. Another train arrives at the station 18 minutes later, repeating

nadya68 [22]

$|\Omega|=20\\|A|=2\\\\P(A)=\dfrac{2}{20}=\dfrac{1}{10}=10\%$

4 0

3 years ago

Read 2 more answers

Using diagonals from a common vertex, how many triangles could be formed from the polygon pictured below?

Ad libitum [116K]

9514 1404 393

Answer:

Step-by-step explanation:

From a given vertex, two of the vertices are adjacent, so a "diagonal" to those will not form a triangle. The number of diagonals that can be drawn is 3 fewer than the number of sides. The number of triangles is 1 more than the number of diagonals.

For a 5-sided figure, 2 diagonals can be drawn from a common vertex.

3 triangles will be formed.

8 0

3 years ago

Find z1z2 if z1 = 2/5(cos63° + isin63°) and z2 = 10/3(cos117° + isin117°).

Airida [17]

Answer:

-10/3 is the answer

Step-by-step explanation:

Given are two complex numbers as

$z1=\frac{2}{5} (cos63 + isin63)\\z2=\frac{10}{3} (cos 117 + isin117})$

Recall Demoivre theorem as

(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)

Hence here we have sum of angles as

A+B = 63+117 =180

$z1z2=\frac{2}{5} \frac{10}{3} (cos180+isin180)$

= $\frac{-10}{3}$

Since sin180=0 and cos 180=-1

7 0

4 years ago