Question

How many grams are there in 3.3 x 10^23 atoms of boron?

Answer 1

5.924 g

Step-by-step explanation:

The average weight of a boron atom is 10.811 atomic mass units (AMU). Therefore 3.3 x 10^23 atoms of boron will weight;

3.3 x 10^23 * 10.811 = 3.56763 x 10 ^ 24

One (1) gram = 6.022 x 1023 AMU. Therefore to convert AMU to grams;

3.56763 x 10 ^ 24 / 6.022 x 10^23

= 5.924 g

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