Using the cosine function:
Solve for b:
![\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%3D16%5Ccdot%5Ccos%20%2845%29%20%5C%5C%20b%3D8%5Csqrt%5B%5D%7B2%7D%20%5Cend%7Bgathered%7D)
Answer:
9/32
Step-by-step explanation:
3 5/9
=> (27+5)/9
=> 32/9
Reciprocal of 32/9 is,
=> 9/32
When y = 2, x = 8.
This can be written as: 2/8.
Simplified: 1/4
True
D because you have to distribute the twelve to complete the equation
Answer:
x = - 3 ± √27 or if you want it in decimal form correct to nearest hundredth:
x = -8.20, 2.20.
Step-by-step explanation:
x^2 + 6x - 18 = 0
this will not factor so we use completing the square:
x^2 + 6x = (x + 3)^2 - 9 so:
(x + 3)^2 - 9 - 18 = 0
(x + 3)^2 = 27
x+ 3 = ±√27
x = - 3 ± √27
