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goblinko [34]
3 years ago
5

What is the equation in standards form of the line y=1/9x+5

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0
X - 9y = -45 i’m not sure what line ? but this is in standard form
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Do you have chart for measuring liquid ?
True [87]
It's called a measuring cup.
6 0
3 years ago
Read 2 more answers
8.) Write y = 3/5 x + 4 in standard form using integers.
Tju [1.3M]

Answer:

I believe the answer is c

Step-by-step explanation:

What i got tho was... 3x-5y=-20

7 0
3 years ago
Help quick please. Order the numbers from least to greatest.
Anastasy [175]

Answer:

-2\frac{1}{4}

Step-by-step explanation:

Mod of any number represents the absolute value of the number.

Therefore, |-2\frac{1}{4}|=2\frac{1}{4} = 2.25

-2\frac{1}{4}=-2.25

|1\frac{1}{4}|=1.25

\frac{3}{4}=0.75

|-1\frac{3}{4}|=1\frac{3}{4}=1.75

-1\frac{1}{4}=-1.25

Now we can arrange these numbers in ascending order.

-2.25 < -1.25 < 0.75 < 1.25 < 1.75 < 2.25

Therefore, -2\frac{1}{4}

4 0
3 years ago
If x+3 is a factor of <br> 2x^2+bx-15<br> what is the value of b?
Mashcka [7]
I hope this helps you

8 0
4 years ago
Plz Help!!!<br> Will Give Brainliest to the First Person that answers!!!
Tatiana [17]

Answer:

15 square units.

Step-by-step explanation:

To find the area, we must find the width and length of the rectangle. To find the width and length, we need to find the length of AB and the length of BC. We use the distance formula.

AB: A(-8, 3); B(-3, 3).

\sqrt{(-8-(-3))^2+(3-3)^2}

= \sqrt{(-8+3)^2+0^2}

= \sqrt{(-5)^2+0}

= \sqrt{25 }

= 5

BC: B(-3, 3); C(-3, 6).

\sqrt{(-3-(-3))^2+(3-6)^2}

= \sqrt{(-3 + 3)^2+(-3)^2}

= \sqrt{(0)^2+9}

= \sqrt{0+9}

= \sqrt{9}

= 3

Now that we have both the width and the length, we can solve for the area using A = lw, where A is the area, l is the length, and w is the width. In this case, l = 5 and w = 3.

A = lw

A = 5 * 3

A = 15

So, the area of the rectangle is 15 square units.

Hope this helps!

8 0
3 years ago
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