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almond37 [142]
3 years ago
5

A grocery store sells a 7 oz bag of raisins for $1.10 and a 9 oz bag of raisins for $1.46. which size bag has the lower price pe

r ounce?
Mathematics
2 answers:
Marysya12 [62]3 years ago
5 0
7 oz bag:
110 ÷ 7 = 15.7143¢ per oz
9 oz bag:
146 ÷ 9 = 16.2222¢ per oz
So the answer is the 7 oz bag, hope this helps!
lozanna [386]3 years ago
5 0
It would be the 7oz bag

hope this helps you
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Step-by-step explanation:

If Candice can paint a room in 6 and Grace can paint one in 8 subtract  and 6 and get 2 hours

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Find the volume of the following cone. Use 3.14 for n and
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SHALL GIVE BRAINLIEST ANSWER!! A ​40% solution of fertilizer is to be mixed with an ​80% solution of fertilizer in order to get
sdas [7]

Answer:

20 gallons of the 40% solution, 60 gallons of the 80% solution

Step-by-step explanation:

Let x = the gallons of the 40% solution, and y = the gallons of a 80% solution. The first thing we want to do here is to convert each percentage into decimal form - including the ​70% solution mixture.

40% = 0.40,

80% = 0.80, respectively 70% = 0.70

As you can tell, 0.40 is associated with x gallons, 0.80 is associated with y gallons, and the mixture contains 0.70 * 80 solution, as 0.70 is associated with 80. Therefore we can formulate the following expression,

0.40x + 0.80y = 0.70 * 80

At the same time x + y = 80, as the solution ( mixture ) is present with 80 gallons. Isolating x, x = 80 - y. Let us plug that into our expression, solving for y, following by x gallons.

0.40\left(\:80\:-\:y\:\right)\:+\:0.80y\:=\:0.70\:\cdot \:80

0.4\left(80-y\right)+0.8y=56 ( Multiply either side by 10 )

4\left(80-y\right)+8y=560 ( Expand )

320-4y+8y=560

320+4y=560

4y=240

y = \frac{240}{4} = 60 ( Substitute to solve for x )

x = 80 - y = 80 - 60 = 20

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3 0
3 years ago
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
3 years ago
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