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iren [92.7K]
4 years ago
6

The height of a cone is twice the radius of its base.

Mathematics
2 answers:
Strike441 [17]4 years ago
5 0

A is the correct answer, i just took the test

OverLord2011 [107]4 years ago
4 0

Option A) 2/3 πx³ is the expression that represents the volume of cone in cubic units.

<u>Step-by-step explanation:</u>

The general formula for the volume of the cone is given by,

⇒ 1/3 πx²h

where,

  • x is the radius of the base of cone.
  • h is the height of the cone.

It is given that,

Height of the cone is twice the radius of its base.

Therefore, the volume of the cone is represented as

⇒ Substitute h=2x in the volume of the cone volume.

⇒ 1/3 πx²(2x)

⇒ 2/3 πx³ cubic units.

Hence, option A) 2/3 πx³ is the expression that represents the volume of cone in cubic units.

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If you know out of 140 pounds, 60 pounds is muscle weight, what is the muscle weight of a 200 pound male?
d1i1m1o1n [39]
You can cross multiply on this and then solve. 

140 / 60 = 200 / x
140x = 12000
x= <span>85.7142857143
x= 85.7</span>
8 0
4 years ago
52.5 ft<br><br> 25 ft<br><br> 22 ft<br><br> 18.18 ft<br> for the picture below
Ugo [173]

Answer:

18.1818181  Feet

Step-by-step explanation:

Divide 27.5 by 20 to establish a ratio between the length and width of the house, then multiply your new ratio by 25. Units do not matter, as long as it's not like 27.5 mm high by .05 ft wide.

6 0
3 years ago
You think of a number from the first thirty negative integers. What is the probability that the integer chosen will be divisible
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Answer:

1/6

Step-by-step explanation:

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Rina8888 [55]

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3 0
3 years ago
Read 2 more answers
(Please Help For Examination) A sweet stall was placing order for making cardboard boxes for packing their sweets. Two sizes of
frozen [14]
Answer: Rs 2,184

Explanation:

1) The statement is incomplete. The complete statement contains the information of the dimensions of both bigger and smaller cardboard boxes.

2) The dimesions of bigger cardboard boxes are 25cm * 20 cm * 5 cm

3) The dimensions of smaller cardboard boxes are 15 cm * 12 cm * 5cm

4) For bigger cardboard boxes:

length, l = 25 cm
width, w = 20 cm
height, h = 5 cm

surface of each bigger carboard box = 2 [ l*w + l*h + w*h] = 2 [25*20 + 25*5 + 20*5] cm^2 = 1450 cm^2

total surface of 250 bigger cardboard boxes = 250 * 1450 cm^2 = 3625,500 cm^2

5% of the total surface area extra = 362,500cm^2 * 5 / 100 = 18,125 cm^2

Total area for bigger cardboard boxes= 362,500 cm^2 +  18,125 cm^2 = 380,625 cm^2

5) Smaller cardboard boxes

length, l = 15 cm
width, w = 12 cm
height, h =  5 cm

surface of each smaller cardboard box = 2 [l*w + l*h + w*h] = 2 [ 15*12 + 15 * 5 + 12 * 5] cm^2 = 630 cm^2

total surface of 250 smaller cardboard boxes = 250 * 630 cm^2 = 157,500 cm^2

5 % extra = 157,500 cm^2 * 5 / 100 = 7,875 cm^2

total area for smaller cardboard boxes = 157,500 cm^2 + 7,875 cm^2 = 165,375 cm^2

6) total area of cardboard required  = 380,625 cm^2 + 165,375 cm^2 = 546,000 cm^2

7) Cost of cardboard required

unit cost per area * total area = (Rs 4 / 1000cm^2) * 546,000 cm^2 = Rs 2,184.

Answer: Rs 2,184
7 0
4 years ago
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