Two dives are tossed once what is the probability that the sum is less than 7
1 answer:
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I'm not sure on what exactly your equation is supposed to be...so I rewrote it
Answer:
- The answer or forecast for temperature using a three-day moving average =
- The answer or forecast for temperature using a three-day moving average =
- The mean absolute deviation based on a two-day moving average, covering all days =
Step-by-step explanation:
1. Three-point averages are calculated by taking a number in the series with the previous and next numbers and averaging the three of them.
Step I - Calculate the three series of succession of numbers form the data and find the average of each of them:
A) (90 + 93 +90)/3 = 91.00
B) (93 + 92 + 90)/3 = 91.67
C) (90 + 92 +90)/3 = 90.67
D) (92 + 90 + 88)/3 = 90.00
E) (90 + 88 + 98)/3 = 92.00
So our series approximated to the nearest whole number is:
91, 92, 91, 90, 92
STEP II
From the series above the highest temperature today is unpredictable because the series is irregular. It went from 91 to 92, then it dropped to 90 and came back to 92.
2. Using a two day moving average we have
STEP I .
Calculate the moving averages
A) (90+93)/2 = 91.50
B) (93 + 90)/2 = 91.50
C) (90 + 92)/2 = 91.00
D) (92 +90)/2 = 91.00
E) (90 + 88)/2 = 89.00
F) (88 + 98)/2 = 93.00
STEP II
The temperature also cannot be predicted because of the irregular series.
3. Calculating the Mean Absolute Deviation based on a two-day moving average
The formula for MAD = (∑||)/
STEP I
To find the mean absolute deviation of the data, start by finding the mean of the data set.
Mean of the data set =
(91.50 + 91.50 + 91.00 + 91.00 + 89.00 +93.00)/6
Mean = 91.17
STEP II
Get the distance between the data point and the mean:
- 91.50-91.17=0.33
- 91.50-91.17= 0.33
- 91.00-91.17= -0.17
- 91.00-91.17= -0.17
- 89.00-91.17= -2.17
- 90.00-91.17= -1.17
STEP II
Add all the distances together
0.33 + 0.33 - 0.17 - 0.17 - 2.17 - 1.17 = -3.02
STEP III
Divide the the sum by data points
-3.02/6
= -0.50
So on average the temperatures were <em>-0.50</em> from the mean.
Cheers!