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Zarrin [17]
4 years ago
11

Which term is most closely related to the crude death rate

Advanced Placement (AP)
2 answers:
kumpel [21]4 years ago
8 0
MORALITY is the closest term related to the crude death rate.
Nimfa-mama [501]4 years ago
7 0

Answer: Mortality rate.

Explanation: The crude death rate is the total number of deaths to residents in a specified geographic area (country, state, etc.) divided by the total population for the same geographic area, for a given year, and multiplied by 100,000.

This can be directly related to the Mortality rate, which is the number of deaths per 1000 individuals in some given region and some given year.

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What was the founding fathers philosophy about human nature
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Which function is an extended function
likoan [24]

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D. The last option

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You can't divide by 0, so find out when the given function is discontinuous.

\frac{x^3+3x^2-x-3}{x^2-1} =\frac{x^3+3x^2-x-3}{(x+1)(x-1)}

You can see that x is discontinuous at x=-1,1, so find a piecewise function that fill in those gaps.

Plug x=-1,1 into your function to find out what values you need to fill in. But of course it's discontinuous at those points, so plug in a number near x=1 and x=-1. I chose x=-1.1 and x=1.1

f(-1.1)\frac{(-1.1)^3+3(-1.1)^2-(-1.1)-3}{(-1.1)^-1} = 1.9 \approx 2

f(1.1)\frac{(1.1)^3+3(1.1)^2-(1.1)-3}{(1.1)^-1} = 4.1 \approx 4

so we need to fill in 2 at x=-1, and fill in 4 at x=1

6 0
3 years ago
The mass of the Sun is 2 × 1030 kg, and the distance between Neptune and the Sun is 30 AU. What is the orbital period of Neptune
Volgvan
<h2>Orbital Period:</h2>
  • To answer this problem, we must employ the gravitational notion and equation. We already know that gravitational force provides the required centripetal force for orbital motion. As a result of matching gravitational and centripetal forces, we may get the equation for orbital time period.
<h2>Answer and Explanation:</h2><h3>Given:</h3>
  • Mass of Sun (M) = 1.99 * 10^30 Kg
  • Orbital radius of the Neptune
  • (R) = 30 A.U. = 30 * (1.496 * 10^11) m
  • R = 44.88 * 10^11 m

Now we know that the time period is given by

T^2 = 4π^2R^3/GM

T^2 = 4π^2*(44.88*10^11)^3/6.67*10^-11*(1.99*10^30)

T = 5.19 * 10^9 s

Now we know that

1 year = 3.154 * 10^7 s

Therefore, T = 5.19*10^9 s/ 3.154 * 10^7 (s/year)

T = 164.4 year

3 0
2 years ago
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