Given:
A submarine dives below the surface, heading downward in 5 moves.
Each move downward = 200 feet
To find:
The location of submarine after it is finished diving.
Solution:
According to the question,
1 move downward = 200 feet
5 move downward = 5 × 200 feet
= 1000 feet
Since, the submarine heading downward in 5 moves, therefore the submarine is 1000 feet downward after it is finished diving.
You could put it in standard form if thats what you mean. in that case its "two thousand seven hundred" or you could also do it in another form which in that case its "2000 + 700"
Answer:\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left( 5^{\frac{3}{2}} \right)^{-\frac{2}{3}}\implies 5^{-\frac{3}{2}\cdot \frac{2}{3}}\implies 5^{-1}\implies \cfrac{1}{5}\implies 0.2 \\\\[-0.35em] ~\dotfill
\bf (256^{0.5})^{1.25}\implies [(2^8)^{0.5}]^{1.25}\implies [2^{8\cdot 0.5}]^{1.25}\implies [2^4]^{1.25}\implies 2^{4\cdot 1.25} \\\\\\ 2^5\implies 32 \\\\[-0.35em] ~\dotfill\\\\ ( 81^{-\frac{1}{6}} )^{\frac{3}{2}}\implies [(3^4)^{-\frac{1}{6}} ]^{\frac{3}{2}}\implies 3^{4\cdot -\frac{1}{6}\cdot \frac{3}{2}}\implies 3^{-\frac{12}{12}}\implies 3^{-1} \\\\\\ \cfrac{1}{3}\implies 0.33...
Step-by-step explanation: I don’t really know about inequalities can y’all help?
Answer:
48
Step-by-step explanation:
multiply both sides by 4
12 times 4 is 48
Answer: Part A is - the highest frequency was 5
The total number of the frequency is 24
The range is 1
I gave you the best answer that I have. I did my best. Good luck! :)
Step-by-step explanation:
