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GalinKa [24]
3 years ago
14

HELP WITH MATH!!!!!!!!!!!!

Mathematics
1 answer:
Leno4ka [110]3 years ago
8 0

Answer:

<em>B.) 1.13s; 27.25ft</em>

Step-by-step explanation:

<em>Ok so this is an projectile motion equation...</em>

<em>Haven't done one of these in a while but I could definitely try!</em>

<em>To do this, we need to use this particular equation</em>

<em />t = \frac{-b}{2a}<em />

<em>We can substitute values into the equation to get the time it takes to reach the maximum height!</em>

t = \frac{-36}{2(-16)} \\

<em>This is the same as...</em>

<em />t = 1.13<em />

<em>We now know that it takes 1.13 seconds for the ball to reach its maximum height!</em>

<em>We can insert that into the original equation and simplify to get this answer:</em>

<em />= -16(1.13)^{2} +36(1.13)+7\\= -16(1.28) + 40.68 +7\\= -20.48 +47.68\\=27.20<em />

<em>Alright so it's not exactly 27.25 but you get the gist.</em>

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Solve the following system pf equations
mr Goodwill [35]

Answer:

Step-by-step explanation:

If you need to do this by graphing, you need to change the format of each equation into slope intersect form

start with 3x-2y=-24

-2y=-3x-24

y=-3/2x+12

To graph this, the y intersect (where it crosses the y axis) is 12 and from there the slope is -3/2

For the next equation,

-3x-y=6

-y=3x+6

y=-3x-6

So the y intersect is -6 and the slope is -3.

Once you graph both of these, the point where both lines cross AKA the intersecion is the solution to the problem.

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3 years ago
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GuDViN [60]
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It cost $520 to plant 4 acres of corn. How much would it cost to plant 3/5 acre of corn?
VLD [36.1K]
Importance should be given to all the informations that are already given in the question. based on those information's, the answer to the question can be easily determined.
The cost of planting 4 acres of corn = 520 dollars
Then
the cost of planting 1 acre of corn = (520/4) dollars
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So
The cost of planting 3/5 acres of corn = (3/5) * 130 dollars
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So the cost of planting 3/5 acre of corn is $78. I hope the procedure is clear enough for you to understand. You can always use this method in future for solving similar type of problems without requiring any help from outside.
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