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GalinKa [24]
3 years ago
14

HELP WITH MATH!!!!!!!!!!!!

Mathematics
1 answer:
Leno4ka [110]3 years ago
8 0

Answer:

<em>B.) 1.13s; 27.25ft</em>

Step-by-step explanation:

<em>Ok so this is an projectile motion equation...</em>

<em>Haven't done one of these in a while but I could definitely try!</em>

<em>To do this, we need to use this particular equation</em>

<em />t = \frac{-b}{2a}<em />

<em>We can substitute values into the equation to get the time it takes to reach the maximum height!</em>

t = \frac{-36}{2(-16)} \\

<em>This is the same as...</em>

<em />t = 1.13<em />

<em>We now know that it takes 1.13 seconds for the ball to reach its maximum height!</em>

<em>We can insert that into the original equation and simplify to get this answer:</em>

<em />= -16(1.13)^{2} +36(1.13)+7\\= -16(1.28) + 40.68 +7\\= -20.48 +47.68\\=27.20<em />

<em>Alright so it's not exactly 27.25 but you get the gist.</em>

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45+55=100 180-100=80 that makes y = 80, and vertical angles makes x=80
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Answer: B has greater spread than A.

Step-by-step explanation:

Since we have given that

Set A: {38, 12, 23, 48, 55, 16, 18}

Range of A = Highest - Lowest

Range of A =  55  -  12

Range of A = 43

Set B:{44, 13, 24, 12, 56}

Range of B = Highest - Lowest

Range of B =    56      -     12

Range of B =       44

Since Range of B is more than range of A.

Hence, B has greater spread than A.

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Step-by-step explanation:

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The slope and length of the given sides of the quadrilateral can be

found by using the coordinates of the vertices.

Correct responses:

  • Slope \ of \ \overline{IJ} = \underline{-\dfrac{7}{6} },      Length of \overline{IJ} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{JK} = \underline {-\dfrac{2}{9}},     Length of \overline{JK} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{KL} = \underline{-\dfrac{7}{6} },      Length of \overline{KL} = \underline{\sqrt{85}}
  • Slope \ of \  \overline{LI} = \underline{ -\dfrac{2}{9} },        Length of \overline{LI} = \underline{\sqrt{85} }

<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

K(-7, 0), J(2, -2), I(8, -9), L(-1, -7)

  • Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}

  • Length \ of \ line =  \mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}

Therefore;

Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}

Slope \  of \ \mathbf{\overline{JK}} = \dfrac{0 - (-2)}{-7 - 2}  = \dfrac{2}{-9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{JK}} = \sqrt{(-7 - 2)^2 + (0 - (-2))^2}  = \underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length  \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{LI}} = \dfrac{(-9 - (-7))}{(8 - (-1))} = \dfrac{-2}{9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}

Learn more about finding the slope and length of a line here:

brainly.com/question/11612395

brainly.com/question/14039630

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