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Alex
3 years ago
12

Find all solutions to the equation secx(2 cosx-sqrt 2)=0

Mathematics
2 answers:
Lisa [10]3 years ago
7 0
We are given with the equation <span>secx(2 cosx-sqrt 2) = 0</span>
ollegr [7]3 years ago
6 0
Hello,

We suppose x≠+/-π/2.

2cos x - √2=0
==>cos x=√2/2
==>x= π/4 or x=3π/4 (modulo 2π)
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11 people. Hope this helped!!
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Dear algebra stop asking us to find your x don't ask y​
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Find the H.C.F of 48,60 and 96. please no links . please step by step explanation​
krek1111 [17]

Answer:

Do you mean GCF?

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2 years ago
I kind of understand this question, but I'm not sure how to answer it directly, can someone help please.
nordsb [41]
So here we use the pythagorean theorem which is a2 + b2 = c2 (“a” squared times “b” squared equals “c” squared) the length from calvins house to the intersection is “a” and the length from phoebes house to the intersection is “b” so in order to find out the length of “c” (calvins house to phoebes house) we need to use the pythagorean theorem

a2 275x275=75,625

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so now that we have figured out what a2 and b2 are let’s add them

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now since we only need to find out the length and not the area we need to find the square root of 88,394

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5 0
3 years ago
Suppose that
Diano4ka-milaya [45]

Answer:

sin(B) = 12/13

cos(B) = 5/13

tan(B) = 12/5

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sec(B) = 13/5

cot(B) = 5/12

Step-by-step explanation:

If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:

BC = 5\\AC = \sqrt{13^2 - 5^2}\\AC = 12

The six  trigonometric functions of angle B are:

sin(B) =\frac{AC}{AB}= \frac{12}{13}\\cos(B) = \frac{BC}{AB} =\frac{5}{13}\\tan(B) = \frac{AC}{BC} =\frac{12}{5}\\\csc(B) =\frac{1}{sin(B)}= \frac{13}{12}\\sec(B) = \frac{1}{cos(B)} =\frac{13}{5}\\cot(B) = \frac{1}{tan(B)} =\frac{5}{12}\\

7 0
3 years ago
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