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3 years ago

How many tenths are in 3ones

Mathematics

1 answer:

Vinil7 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Each one has 10 tenths, so 3 ones have 30 tenths.

You can do this by dividing 3 by 1/10.

3/(1/10) = 3/1 * 10/1 = 30/1 = 30

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Find an equation of a line with the x- and y-intercepts below. Use exact fractions when necessary.

tamaranim1 [39]

Answer:

$y=\frac{5}{7}x-5$

Step-by-step explanation:

All lines in the plane are of the form

y = mx+b

The intersection with the Y-axis is obtained by replacing x with 0

The intersection with the X-axis is obtained by replacing y with 0

If we want that the Y-intercept = -5, then

-5 = m(0)+b

So b = -5

Our temporal equation is then

y = mx-5

If we want that the X-intercept = 7, then

0 = m(7)-5

7m = 5

m = 5/7

So our final equation is

$y=\frac{5}{7}x-5$

Attached is the graph of the line

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3 years ago

Write a expression only using positive exponents 9c3/c -4

SOVA2 [1]

Answer:

ok sooo

Step-by-step explanation:

2x - 5 + - x - 2

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3 years ago

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ZanzabumX [31]

Answer:

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Step-by-step explanation:

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3 years ago

If XYZ measures 45°, what is the measure of ?

ololo11 [35]

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3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

dusya [7]

$(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}$

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

$\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}$

7 0

3 years ago

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