You want to find the measure of angle x. Rearrange the given 8 cos x+3=0 as <span>8 cos x= -3, or cos x = -3 / 8, or cos x = -0.375.
Use the arccos function (inverse cosine) to find the value of x in radians and in degrees.
Since the cosine function is negative only in Quadrants II and III, focus on the following possible ranges: Quadrant II: 90 < x < 180 and
Quadrant III: 180 < x < 270.
Example: using my calculator to obtain the inverse cosine of -0.375, I got x = 1.96 radians. Convert this into degrees if desired. Draw a ray showing this angle. Reflect this ray across the horiz. axis to obtain the angle in Q III.</span>
<span>The total distance of the route on the map is 3 in. + 2 in. + 1.5 in. + 0.25 in. = 6.75 in. The actual distance is 135 feet, so the scale is 6.75 in. = 135 feet. Dividing 135 by 6.75, the scale is 1 in. = 20 feet.</span>
Answer:
Answer:
y = -5(x - 7)^3 - 1
Step-by-step explanation:
You kind of just plug in the numbers.
a vertical stretch by a factor of 5: y = 5x^3
a reflection across the x-axis: y = -5x^3
a vertical translation 1 unit down: -5x^3 - 1
a horizontal translation 7 units right: -5(x - 7)^3 -1
Step-by-step explanation:
There you go
.........................
Make up linear functions f(x) and g(x). Explore, with diffefent pairs of f(x) and g(x) the graphs for
i. h(x) = f(x) + g(x)
ii. h(x) = f(x).g(x)
iii. h(x) = f(x)/g(x)
iv. h(x) = f(g(x))
Summarize and illustrate."