Madison claims that two data sets with the same median will have the same variability. Which data set would provide good support
for whether her claim is true or false? Her claim is true and she should use these data sets to provide support.
A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7.
A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 6.
Her claim is true and she should use these data sets to provide support.
A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7.
A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 5 to 8. A line divides the box at 7.
Her claim is false and she should use these to show that two data sets with the same median can have different variability.
A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7.
A box-and-whisker-plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 5 to 8. a line divides the box at 7.
Her claim is false and she should use these to show that two data sets with the same median can have different variability.
A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7.
A box-and-whisker-plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 5 to 8. a line divides the box at 5.5.
Increasing a price by 50% is like adding half of the original price to get an updated price. 42 times 50% or divided by 2 (Since it produces the same result) is 21 and 21 plus 42 is 63. 63 dollars is the correct answer which means the correct option is option A.
