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statuscvo [17]
3 years ago
12

Please help me. Dont judge.

Mathematics
2 answers:
crimeas [40]3 years ago
7 0
The answer is A. Because to get rid of the five you have to do reverse property so if it's subtraction you'd change it to adding to get rid of the 5
tia_tia [17]3 years ago
6 0
It would be A because u need to add 5
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Determine the values of the constants B and C so that the function given below is differentiable.
laila [671]
For the function to be differentiable, its derivative has to exist everywhere, which means the derivative itself must be continuous. Differentiating gives

f'(x)=\begin{cases}24x^2&\text{for }x1\end{cases}

The question mark is a placeholder, and if the derivative is to be continuous, then the question mark will have the same value as the limit as x\to1 from either side.

\displaystyle\lim_{x\to1^-}f'(x)=\lim_{x\to1}24x^2=24
\displaystyle\lim_{x\to1^+}f'(x)=\lim_{x\to1}B=B

So the derivative will be continuous as long as B=24

For the function to be differentiable everywhere, we need to require that f(x) is itself continuous, which means the following limits should be the same:

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}8x^3=8
\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}Bx+C=24+C

24+C=8\implies C=-16

So, the function should be

f(x)=\begin{cases}8x^3&\text{for }x\le1\\24x-16&\text{for }x>1\end{cases}

with derivative

f'(x)=\begin{cases}24x^2&\text{for }x
5 0
4 years ago
Based on the graph of the line below, which describes the relationship between the value of the y-intercept and the
stepan [7]

Answer:

y intercept = 3

m = \frac{1}{3} --- slope

Step-by-step explanation:

Given

The attached graph

Required

Determine the slope and the y intercept

The y\ intercept is at the point where x = 0.

From the graph:

y = 3;\ when\ x = 0

Hence,

y intercept = 3

Next, we calculate the slope using:

m = \frac{y_1 - y_2}{x_1 - x_2}

Where:

(x_1,y_1) = (0,3)

(x_2,y_2) = (9,6)

So, we have:

m = \frac{3 - 6}{0 - 9}

m = \frac{-3}{- 9}

m = \frac{3}{9}

m = \frac{1}{3}

6 0
3 years ago
A spring stretches out by 8cm when a 0.2 kg weight is placed on it. How much does the spring stretch by when a 0.5 kg weight is
Ierofanga [76]

m₁ = mass hanged initially = 0.2 kg

x₁ = initial stretch in the spring = 8 cm = 0.08 m

k = spring constant of the spring

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₁ = m₁ g

k (0.08) = (0.2) (9.8)

k = 24.5 N/m


m₂ = mass hanged later = 0.5 kg

x₂ = final stretch in the spring = ?

k = spring constant of the spring = 24.5 N/m

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₂ = m₂ g

(24.5) x₂  = (0.5) (9.8)

x₂  = 0.2 m = 20 cm



5 0
3 years ago
In △QRS, QR¯¯¯¯¯¯¯¯ has been bisected at point T, and TU¯¯¯¯¯¯¯ has been drawn such that U is the point of intersection of TU¯¯¯
Allushta [10]

9514 1404 393

Answer:

  ∠RTU≅∠TQS

Step-by-step explanation:

To show TU ║ QS, the angles made by transversal RQ with each of those segments must be shown to be congruent. That is, it must be true that ...

  ∠RTU≅∠TQS

5 0
3 years ago
Which of the following is th least
Nookie1986 [14]
Which is the least of what!?
6 0
4 years ago
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