Answer:
See below
Step-by-step explanation:
- <em>aⁿ = a×a×a×....×a (power n of the number a = number a multiplied by itself n times)</em>
2^(10)= 2x...x2 how many times = 10 times 2
15^(57)= 15x...x15 how many times = 57 times 15
(-4)x...x(-4) 7 times = (-4)^(7)
(1.5)x...x(1.5) 12 times = (1.5)^(12)
9514 1404 393
Answer:
a) 24×10^-7
Step-by-step explanation:
The number is ...
0.0000024 = 2.4×0.000001 = 24×0.0000001
The first of these equivalents can be written as ...
2.4×10^-6 . . . . matches no answer choice (correct answer)
The second of these can be written as ...
24×10^-7 . . . . matches choice (a)
__
Usually "scientific notation" requires there be one digit left of the decimal point in the mantissa. As we have noted above, no offered answer choice matches this form. The only choice that is equivalent to the given number is the one shown above.
There are many reasons one may want to simplify, rearranging to find specific values - or maybe just making it simpler
Well, let's do some examples:
y(x(3+2)) +2 = -2y +2 <span>< I just made this one up, it looks really complicated right now, none the less it can be simplified easily
</span>y(3x+2x) + 2 = - 2y +2
3xy + 2xy + 2 = -2y +2
5xy + 2 = -2y +2 <-- the +2's dissapear because they cancel out
5xy = -2y
<span>And there we have it, that long expression has been simplified to something really simple.
</span>
Another example:
3(4(x+3(2 +z)) - 5)= 3y <span><- you can start where ever, I like starting in the middle
</span>3 * (4 * (x + 3*(2 + z)) - 5 ) = 3y <span><- here it is spaced out, we get a much better view
</span><span>3 * (4 * (x + 6 + 3z) - 5 ) = 3y</span>
3 * (4x + 24 + 12z - 5) = 3y <- divide both sides by 3 ..
4x + 24 + 12z - 5 = y <- much better
<span>
</span>Note: Simplify means solving to a degree, but you can't solve it because it has unknowns
Answer:
20
Step-by-step explanation:
It seems like the rule of this sequence is to add 5 (since 2 + 5 = 7 and 7 + 5 = 12). We already are given that we have 2 2-digit numbers (12 and 17) so let's see if there are any more. The sequence continues to 22, 27, 32, 37, 42, 47, ..., 92, 97. We need to count how many numbers are in the list 12, 17 ... 92, 97. To do this, let's add 3 to every term in the list to get 15, 20, ... 95, 100. Since the list is now full of multiples of 5 we can divide the list by 5 to get 3, 4, ... 19, 20 and then subtract 2 to get 1, 2, ... 17, 18 which means that there are 18 2-digit numbers.
