30 8
+------------------------------------------------------------+-------------------+
I I I
2 I 2 * 30 I 2 * 8 I
I I I
+------------------------------------------------------------+-------------------+
The entire large rectangle above is 38 units long and 2 units wide.
Its area is length times width, so the area is 2 * 38.
38 is also the same as 30 + 8, so the area can also be written as 2(30 + 8).
The left rectangle is 30 units long and 2 units wide. Its area is 2 * 30.
The right rectangle is 2 units long and 8 units wide. Its area is 2 * 8.
If you add the areas of the small rectangles, you get
2 * 30 + 2 * 8
If you add the two small areas, you get the area of the laerge rectangle, so
2(30 + 8) = 2 * 30 + 2 * 8
which is an example of the distributive property.
A square is always a rhombus is the only correct answer.
Answer: 111.72 m^2 if they want round its 112
Is from O to C 14m
A=pixr^2
3.14x14^2= 615.44 m/2 half circle = 307.72
Area of triangle A= 1/2bh. .5x28x14=196
307.72-98=196= 111.72 m^2
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
1: (b+1)*(3b)*(b-5)
(3b^2+3b)(b-5)
3b^3-15b^2+3b^2-10b
3b^3-12b^2-10b
2: πr^ 2(h/3)
π(n-2)^2(12n/3)
π(n-2)(n-2)(12n/3)
π(n^2-2n-2n+4)(12n/3)
π(n^2-4n+4)(12n/3)
π(n^2-4n+4)(4n)
π(4n^3-16n^2+16n)
<em>(I'm not 100% sure with this one)</em>
3: (lwh)/3
((k-2)(2k+3)(3k))/3
((2k^2-4k+3k-6)(3k))/3
(6k^3-12k^2+9k^2-18k)/3
(6k^3-3k^2-18k)/3
2k^3-k^2-6k
The answer is the first option, <-20, -42>.
We can find this by first finding what -2u would equal by multiplying <5, 6> by -2. This gives us <-10, -12>.
Then we need to find out what 5v is equal to, by multiplying <-2, -6> by 5 to get <-10, -30>.
Now that we know what -2u and 5v are, we can substitute them into the equation and get
<-10, -12> + <-10, -30>, which we can split up into -10 - 10 = -20, and -12 - 30 = -42, so your final answer is <-20, -42>.
I hope this helps!
