PLEASE ANSWER ASAP: Danielle's wallet had $2.65 in change:all quarters,dimes and nickels. She had 3 times as many quarters as di

Question

Alchen [17]

4 years ago

8

PLEASE ANSWER ASAP: Danielle's wallet had $2.65 in change:all quarters,dimes and nickels. She had 3 times as many quarters as di

mes and one more dime than nickels. How many of each coin did she have?
SHOW WORK

Mathematics

2 answers:

umka21 [38] · Answer 1 · 2021-12-12T05:15:05+03:00

umka21 [38]4 years ago

8 0

2.65=3x(25)+x(10)+(x-1)(5)
9 quarters 3 dimes 2 nickels
9*.25+2.25
3*.10=.30
2*.5=10
2.25+.30+.10=2.65

Butoxors [25] · Answer 2 · 2021-12-12T03:07:34+03:00

Butoxors [25]4 years ago

6 0

We can write an equation in terms of n, the amount of nickels:

25(3n+3)+10(n+1)+5n=265.

Thus:

90n+85=265

Subtracting 85, we have:

90n=180

Therefore, n=2. As such, Danielle has 2 nickels, 3 dimes, and 9 quarters.