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AnnZ [28]
3 years ago
14

What is the missing leg for a triangle with the sides 2 and 3

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0
Root 5 is the answer
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What is 86% of 950? *
muminat

Answer:86%of 950= 817

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
When vector is added to vector , the resultant is vector such that . This resultant vector has components Rx=Ax+BxRx=Ax+Bx and R
SVETLANKA909090 [29]

Answer:

a. When vector is added to vector , the resultant is vector such that its magnitude and direction is proportional to the resultant magnitude and direction of the component vectors.

b. ∅ = tan^{-1}(Rx/Ry)

Step-by-step explanation:

Vectors are used to express physical quantities with magnitude and direction. Vectors can be added by the parallelogram method or the triangular method of addition. the magnitude and direction of the resultant vector is usually proportional to the magnitude and direction of the component vectors.

The direction of the angle is found as

tan∅ = Rx/Ry

∅ = tan^{-1}(Rx/Ry)

6 0
3 years ago
What is the sum of the Linear expression 2n+6 and 6n-2
saveliy_v [14]
Hello there! ^-^ 

To solve, do the following. 

2n + 6 = 8n and 6n - 2 = 4n 

I think you can take it from here ;) 

If not just simply message me

7 0
4 years ago
Calculate the slant height for the given cone. Round to the nearest tenth.
tensa zangetsu [6.8K]
I don't know that answer
7 0
3 years ago
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The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
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