Answer:
The answer to this question is Java,C++.
Explanation:
We can assign non static final variables a value with the declaration or in the constructor but this is not the case with c++ because we have to assign value during declaration and c++ equivalent of final is const keyword and there is sealed or readonly keywords in c# not final.If we do not assign value at the time of declaration the const variable will contain garbage value which cannot be changed afterwards.
Answer:
A) <em><u>a,s,d,f, and either g or caps lock</u></em>
B) <u><em>l,k,j,h, and, ;</em></u>
Explanation:
Answer:
Option 2 i.e., DHCP server.
Explanation:
A client approached the user to ask about their support towards investigating as well as providing necessary equipment required for implementing a SOHO system for his latest house corporation.
So, the following SOHO router functionality facilitates the installation of IP addresses both for the cable and wireless networks on the private server.
A kernel manages the whole computer including hardware. In Unix, all processes are launched from systemd/launchd.
Answer:
0010
Explanation:
Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:
Initial State of the Register:
0000
Group of bits entering:
1011
<u>First Clock Cycle:</u>
0000 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0001
<u>Second Clock Cycle:</u>
0001 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0010 <em>(Final Answer)</em>