Given two functions j(x)=−3x+2 and k(x)=3+4x , what is the function rule for (kj) (x) ?
1 answer:
Answer:
(k·j)(x) = -12x^2 -x +6
Step-by-step explanation:
(k·j)(x) = k(x)·j(x) = (4x+3)(-3x+2) . . . . . substitute function definitions
= 4·(-3)x^2 +(4·2+3(-3))x +3·2 . . . . . multiply using the distributive property
= -12x^2 -x +6
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