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castortr0y [4]
3 years ago
12

How many different ways can 25 students line up for lunch?

Mathematics
2 answers:
zheka24 [161]3 years ago
7 0
25!=15,511,210,043,330,985,984,000,000
aivan3 [116]3 years ago
6 0

Answer:

25!=15511210043330985984000000

Step-by-step explanation:

We are asked to find the number of ways 25 students line up for lunch.

Since there are 25 students, so the students for the 1st place can be chosen in 25 ways.

As 1 student is already chosen for 1st place and there are 24 students left, so the students for the 2nd place can be chosen in 24 ways.  

Since 2 students are already chosen and there are 23 students left, so the students for the 3rd place can be chosen in 23 ways.

We will continue this process till we fill all the 25 places.

\text{The number of ways to line up for lunch}=25*24*23*22*21*20*19*.......*1

We can represent 25*24*23*22*21*20*19*.......*1 as 25!, therefore, 25 students can be line up for lunch in 25!=15511210043330985984000000 different ways.

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Step-by-step explanation:

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HELP WITH MATHHHH PLEASE
Darina [25.2K]

The vertex is at the point (0,0) and the focus at the point (0, 1/8). This is given to us. Both the vertex and focus are separated by a vertical distance in the positive direction.

This means that the parabola opens upward. The vertex form of the equation for a parabola that opens upward is:

y = a(x - h)^2 + k, where the point

(h, k) is the vertex of the parabola.

Plug the vertex given into the above equation.

y = a(x - 0)^2 + 0

y = ax^2 + 0

y = ax^2

What is a?

Note: a = 1/(4f), where f is the distance from the vertex to the focus or simply as given in the focus point above 1/8.

Let f = 1/8

a = 1/4(1/8)

a = 1/(1/2)

a = 2

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y = 2x^2.

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Choice A is the answer.

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